If n is a natural number then the vale of factorial n + factorial n+1 is
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n! + (n+1)!
= n(n-1)! + (n+1)n(n-1)!
=n(n-1)! [ 1 + (n+1) ]
= n(n-1)! [ n+2 ]
= n(n+2) (n-1)!
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Q.) If n is a natural number then we define n! (pronounced as factorial n) to be the product n×(n−1)×(n−2)×....×2×1For example 4! = 4 x 3 x 2 x 1 = 24 If 6! = a!×b! where a > 1 and b > 1 then a + b is _____.
- 6!=3!×2!
- 3!=3×2×1
- 2!=2×1
- 3!+2!=(3×2×1)+(2×1)
- =6+2=8
ans...8
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