Math, asked by Emmabella, 1 year ago

If n is a perfect cube such that n=1000 a +100 b+ 10 c + 1 d and 8000<n<27000, find the values of a,b and c when d=1

Answers

Answered by mdbdhh

N =21^3 =9261
a=9,b=2,c=6

Emmabella: i didn't quite understand

mdbdhh: as n lies between cube of 20 and cube of 30 and according to equation last digit of n is 1 it is only possible if last digit of perfect cube is 1 hence n is cube of 21

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