If n is a positive integer such that 8n + 1 is a perfect square, then
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If nn is a positive integer greater than 1 such that 8n+1 is perfect square, then find n+1 is the sum of three perfect squares
8n+1=x^2
8n+1+7=x^2+7
8(n+1)=x^2+7
n+1=x^2+7/8
8n+1=x^2
8n+1+7=x^2+7
8(n+1)=x^2+7
n+1=x^2+7/8
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