If n is a positive integer then how many values of n will give an integral value of
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Now, for any value of n, it must divide the 16n2 and 7n but the divisibility of 6 by n is dependent on three values i.e., 2,3 and 6 (all three are the factors of number 6). So, for n = 2,3 and 6 , the term possess integral value. Hence, there are 3 values of n for which the term possess integral value.
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