Question

if n is a positive odd integer then integration of modulus of x to the power of n into dx is equals to​

Answer 1

Answer:

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Answer 2

$\int | {x}^{n} | dx$

Will be equal to

$\int {x}^{n} dx \: \: \: \: \: \: \: \: \: x > 0$

and

$- \int {x}^{n} dx \: \: \: \: \: \: \: \: \: \: x < 0$

$= > \int {x}^{n} = \frac{ {x}^{n + 1} }{n + 1} + c \: \: \: \: \: \: \: \: \: \: \: \: \: \: x > 0$

and

$= > - \int {x}^{n} = - \frac{ {x}^{n + 1} }{n + 1} + c \: \: \: \: \: \: \: \: \: \: \: \: \: \: x < 0$