Question

If n is a rational number, then 5^2n − 2^2n is divisible by
(A) 3

(B) 7

(C) Both 3 and 7

(D) None of these

Answer 1

option (c)

The number is divisible by both 7 and 3

Step-by-step explanation:

If n is a rational number

then $5^2^n - 2^2^n$ is in the form of $a^2^n - b^2^n$

which is divisible by both  (a+b) and (a-b)

so, here , a = 5  and b = 2

therefore ,  5+2 = 7 , 5-2=3

thus ,

$5^2^n - 2^2^n$  is divisible by both 7 and 3

hence ,

option (c)

The number is divisible by both 7 and 3

#Learn more:

If n is odd natural numbers then 3^2n+2^2n is always divisible by

https://brainly.in/question/14225936

Answer 2

Answer:

option (c) will be the right answer!!

The number is divisible by both 7 and 3

Step-by-step explanation:

If n is a rational number

then 5^2n - 2^2n is in the form of a^2n - b^2n

which is divisible by both (a+b) and (a-b)

so, here , a = 5 and b = 2

therefore , 5+2 = 7 , 5-2=3

thus ,

5^2n - 2^2n is divisible by both 7 and 3

hence ,

option (c)

The number is divisible by both 7 and 3