Question

If n is a three digit number and last two digits
of square of n are 54 (n2 = … 54), then how many values of n are possible?
​

Answer 1

Answer:

sorry I can't answer you

Step-by-step explanation:

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Answer 2

Answer:

Zero

Step-by-step explanation:

n^2=...54, square of n is even number and thus n is even number.

The square of even number n=2k is n^2=4k^2.

It must be divisible by 4.

Divisibility rule 4 says "If the last two digits of a whole number are divisible by 4, then the entire number is divisible by 4".

Our number ends with 54 and it is not divisible by 4:  

• 54/4=13 rem 2

So there is no such 3 digit number.

Answer is zero