If n is an eight digit number and s(n) denotes the sum of its digits
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Therefore, that can be simplified to 10*((1+9)/2)*9=90*10/2=450. That was the sum of the digits in the 1s place from 1–100. But we also need to add the digits in the 1s place from 101–108. Therefore, the sum of all the numbers in the 1s place is 450 + 36 = 486
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