Question

If n is an integer between 0 and 21 , then the minimum value of n!(21 - n)! is attained for n =

Answer 1

Multiply and divide n!(21-n)! by 21!, you get n!(21-n)! = 21!/21 C n


so,minimum value of the given term is same as maximum of 21 C n


we know the max of N c r is for r = n-1/2 if n is odd


therefore for n= 10 or 11 {both same value}, 21 C n is maximum ,hence given term is minimum


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Answer 2

Answer:

HEY Buddy here's ur answer

Multiply and divide n!(21-n)! by 21!, you get n!(21-n)! = 21!/21 C n

so,minimum value of the given term is same as maximum of 21 C n

we know the max of N c r is for r = n-1/2 if n is odd

therefore for n= 10 or 11 {both same value}, 21 C n is maximum ,hence given term is minimum

Step-by-step explanation: