Math, asked by Govind12390, 11 months ago

if n is an odd integer then show that n^2 -1 is divisible by 8

Answers

Answered by officialsinghrs
3

Answer:

Good Luck :)

Step-by-step explanation:

we know ,

odd number in the form of (2P +1) where P is a natural number ,

so, n² -1 = (2P + 1)² -1

= 4P² + 4P + 1 -1

= 4P² + 4P

now , checking :

P = 1 then,

4P² + 4P = 4(1)² + 4(1) = 4 + 4 = 8 , it is divisible by 8.


P =2 then,

4P² + 4P = 4(2)² + 4(2) =16 + 8 = 24, it is also divisible by 8 .


P =3 then,

4P² + 4P = 4(3)² + 4(3) = 36 + 12 = 48 , divisible by 8


hence, we conclude that 4P² + 4P is divisible by 8 for all natural number .

hence, n² -1 is divisible by 8 for all odd value of n .




Govind12390: 4p kaha se aaya
officialsinghrs: Odd number is in the form of (2P+1)
officialsinghrs: so, n² -1 = (2P + 1)² -1
officialsinghrs: (a+b)² ka formulae
Govind12390: thanks very much
officialsinghrs: Pleasure :)
Govind12390: ^_^
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