If n is an odd positive integer, show that n²-1 is divisible by 8
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We kno tat any odd positive integer is of the form 4q+1,4q+3
When n=4q+1,
n^2-1=(4q+1)^2-1
=16q^2+8q+1-1
=16q^2+8q
=8q(2q+1)
n^2-1 is divisible by 8
As in the same way try with 4q+3 also
When n=4q+1,
n^2-1=(4q+1)^2-1
=16q^2+8q+1-1
=16q^2+8q
=8q(2q+1)
n^2-1 is divisible by 8
As in the same way try with 4q+3 also
manaalbn:
why 4??
Bcoz we hav to get 8 kno
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