if n is an odd positive integer then show that n square-1 is divisible by 8
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if n is odd positive integer , then let n = 3 ,5 ,9..... and so on..
so first let n=3
therefore n²=3²=9
n²-1=9-1=8 .which is divisble by 8
now let n=5
therefore n²=5²=25
n²-1=25-1=24. which is also divisible by 8
therefore any odd positive integer which has equation n²-1 is divisible by 8
so first let n=3
therefore n²=3²=9
n²-1=9-1=8 .which is divisble by 8
now let n=5
therefore n²=5²=25
n²-1=25-1=24. which is also divisible by 8
therefore any odd positive integer which has equation n²-1 is divisible by 8
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