Question

If n is an odd positive integer then the value of 1 + (i)^2n +(i)^4n + (i)^6n is :
A)-4i
B)0
C)4i
D)4

Answer 1

Answer:

If n is an odd positive integer then the value of 1 + (i)^2n +(i)^4n + (i)^6n is :

A)-4i