If'n' is any natural number, then (12)" cannot end with the digit:
a-2 b-4 c-8 d-0
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Answer:
Here, Number 12
n
where nϵN
Now 12
n
=(2
2
×3)
n
Now, for 12
n
to end with 0, it should have 2 as well as 5 in its prime factors. Also to end with 5, of require at least a single multiple of 5 in its prime factors, so 12
n
cannot end with the digit 0 or 5.
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