Question

if n is equal to 2 ki power 3 into 3 ki power 4 into 5 ki power 4 into 7 then the number of consecutive zero in an where n is a natural number is
​

Answer 1

Given:

$2^{3} \times 3^{4} \times 5^{4} \times 7$

Find:

consecutive zero in n, where n is a natural number is

​Solution :

So here

=> n = $2^{3} \times 3^{4} \times 5^{4} \times 7$

we can write it as :

$\begin{array}{l}n=2^{3} \times 3^{4} \times 5^{3} \times 5 \times 7 \\\\n=(2 \times 5)^{3} \times 3^{4} \times 5 \times 7 \\\\n=(10)^{3} \times 3^{4} \times 5 \times 7\end{array}$

$n=3^{4} \times 5 \times 7 \times 1000$

So here are three zeros

Hence the consecutive zero in n are three(3)