Math, asked by aaravi11, 1 year ago

if n is equal to 2 raise to power 3 into 3 raise to power 4 into 5 raise to power 4 into 7 then the number of consecutive zeros in n a n is a natural number is what please tell me briefly please please please​

Answers

Answered by waqarsd
40

check the attachment

hope it helps

Attachments:
Answered by ghrithabs2006
4

Answer:

3 is the correct answer

Step-by-step explanation:

n= 2^3 × 3^4 × 5^4 × 7

bring (2^3) and (5^4) together

2^3 × (5^3 ×5)

2^3× 5^3 (5 × 3^4 × 7)

(10)^3 (5 × 3^4 × 7)

1000 (5 × 3^4 × 7)

this expression contains 3 zeroes as a result the number of consecutive zeroes in n is three

Thank you

hope it helps you

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