if n is equal to 2 raise to power 3 into 3 raise to power 4 into 5 raise to power 4 into 7 then the number of consecutive zeros in n a n is a natural number is what please tell me briefly please please please
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Answer:
3 is the correct answer
Step-by-step explanation:
n= 2^3 × 3^4 × 5^4 × 7
bring (2^3) and (5^4) together
2^3 × (5^3 ×5)
2^3× 5^3 (5 × 3^4 × 7)
(10)^3 (5 × 3^4 × 7)
1000 (5 × 3^4 × 7)
this expression contains 3 zeroes as a result the number of consecutive zeroes in n is three
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