If n is even number then the remainder when (x^n-1)is divided by (x+1)=____________
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using the remainder theorem
x+1=0
x= -1
putting the value of x in the polynomial
(-1)to the power n - 1
since n is even, therefore, the value will always be
1 -1
=0.
x+1=0
x= -1
putting the value of x in the polynomial
(-1)to the power n - 1
since n is even, therefore, the value will always be
1 -1
=0.
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