If n is odd then 1+i2n+i4n+i6n=?
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Answered by
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hey mate ☺️...here is the answer
If n is odd then
1+i^2n+i^4n+i^6n = 0
In the question,
The expression of the term,
1 + i^{2} +i^{4}+i^{6}+..........i^{2n}
When the value of 'n' is odd.
We can say that,
1 + i^{2} +i^{4}+i^{6}+..........i^{2n}=(1 + (-1)) +(1+(-1))+......(1+(-1))=0
Answered by
0
Answer:
option c 0
Step-by-step explanation:
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