Math, asked by sheetalharshi, 9 months ago

If n is odd then 1+i2n+i4n+i6n=?​

Answers

Answered by vanshikavikal448
3

hey mate ☺️...here is the answer

If n is odd then

1+i^2n+i^4n+i^6n = 0

In the question,

The expression of the term,

1 + i^{2} +i^{4}+i^{6}+..........i^{2n}

When the value of 'n' is odd.

We can say that,

1 + i^{2} +i^{4}+i^{6}+..........i^{2n}=(1 + (-1)) +(1+(-1))+......(1+(-1))=0

Answered by lalsinghdilipsingh
0

Answer:

option c 0

Step-by-step explanation:

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