Math, asked by kovvurisupraja4500, 9 months ago

If N is product of even numbers from 2 to 100 and N is divisibly by 4725^n,find the largest possibility value of n.

Answers

Answered by akshitaras123
0

Step-by-step explanation:

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GMAT Club Forum Index Problem Solving (PS)

If n is a positive integer and n^2 is divisible by 72, then : Problem Solving (PS)

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amitvmane

Mar 31, 2012

00:00ABCDE

DIFFICULTY: 55% (hard) QUESTION STATS: based on 2845 sessions

60% (01:24) correct

40% (01:43) wrong

If n is a positive integer and n^2 is divisible by 72, then the largest positive integer that must divide n is

A. 6

B. 12

C. 24

D. 36

E. 48

Spoiler: OA

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Most Helpful Expert Reply

Bunuel

EXPERT'S

POST

Mar 31, 2012

If n is a positive integer and n^2 is divisible by 72, then the largest positive integer that must divide n is

A. 6

B. 12

C. 24

D. 36

E. 48

The largest positive integer that must divide , means for the least value of which satisfies the given statement in the question. The lowest square of an integer, which is multiple of is --> --> . Largest factor of is .

OR:

Given: , where is an integer (as is positive).

--> , as is an integer , also must be an integer. The lowest value of , for which is an integer is when --> -->

Answered by 11yusunami07
1

Answer:

If we can use log,

log4721 100=n

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