If n is the bisector of line segement AB, then OA
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Line l⊥AB and passes through C which is the midpoint of AB
To show that PA=PB
In △PCA and △PCB
AC=BC since C is the mid-point of AB
∠PCA=∠PCB=90
∘
(given)
PC=PC(common)
So,△PCA≅△PCB by SAS rule.
and so PA=PB as they are corresponding sides of congruent triangles
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