if n(p) =8 and n(q) =5 find maximum and minimum number elements in p union q
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Given :-
- n ( P) = 8
- n ( Q) = 5
To find :-
- maximum no. of elements in P ∪ Q
- minimum no. of elements in P ∪ Q
Solution :-
As we know,
→ n(P ∪ Q) = n(P) + n(Q) - n(P ∩ Q)
so,
→ n(P ∪ Q) = 8 + 5 - n(P ∩ Q)
→ n(P ∪ Q) = 13 - n(P ∩ Q)
Now,
∵ The minimum no. of elements in P∩Q is zero, when P and Q are disjoint sets.
∴ maximum no. of elements in P∪Q =13 - 0
= 13
and
∵ The maximum no. of elements in P∩Q is 5,when all the elements of set Q are present in set P
∴ Minimum no. of elements in P∪Q = 13 - 5
= 8 .
Therefore,
Minimum no. of elements in P ∪ Q = 8
maximum no. of elements in P ∪ Q = 13
so,
we can say that
8 ≤ n ( P∪Q ) ≤ 13 .
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