Question

if n(P (A)) = 1024, n(AUB) = 15 and n(P())=32 then find n(AnB)​

Answer 1

n(P( A)) = 1024 = 210 ⇒ n( A) = 10 n(A ∪ B) = 15 n(P(B)) = 32 = 25 ⇒ n(B) = 5 We know n(A ∪ B) = n{A) + n(B) – n(A ∩ B) (i.e.) 15 = 10 + 5 – n(A ∩ B) ⇒ n(A ∩ B) = 15 – 15 = 0

Answer 2

Step-by-step explanation:

n[p(a)]=1024

2n(a)=1024

2n(a)=2^10

like wise for np(b)=2^5