Question

If n (P (A))=1024, n (AUB)=15 and n(P(B))=32, then find intersection

Answer 1

Answer:

Step-by-step explanation:

n(AΠB)=n(A)+n(B)-n(AUB)

=1024+32-15=1041.

Answer 2

Given :

• n(A) = 1024

• n(A∪B) = 15
• n(B) = 32

$\rule{200}{2}$

To Find :

We have to find the intersection [n(A∩B)]

$\rule{150}{2}$

Solution :

We know the formula to calculate the intersection.

⇒ n(A∪B) = n(A) + n(B) - n(A∩B)

→ n(A∩B) = n(A) + n(B) - n(A∪B)

→ n(A∩B) = 1024 + 32 - 15

→ n(A∩B) = 1056 - 15

→ n(A∩B) = 1041