Question

if n(p(A))=1024,n(AUB)=15 and n(P(B))/=32,then find n(A intersection B).​

Answer 1

Step-by-step explanation:

Solution,

n (p(A) = 1024

n (AUB) = 15

n (p(B) = 32

Now,

n (AUB) = n(p (A) + n (p (B) - (AnB)

or, 15 = 1024 + 32 - n (AnB)

or, n(AnB)= 1056 - 15

or, n(AnB)= 1041

Hence ,

n (AnB) = 1041

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