Question

if n(p(A))=1024,n(AUB)=15 and n(p(B))=32,then find n(AUB).

Answer 1

I think n(A intersection B) = 15.
Then..

Given,
n(p(A))= 1024
n(A intersection B) = 15
n(p(B))=32

Therefore,
n(AUB) = n(p(A))+n(p(B))-n( A intersection B )
= 1024+32-15
= 1056-15
= 1041