Question

if n(p(a))= 1024,n(AUB) =15 and n(p(b)) =32then find n (AnB)​

Answer 1

Answer:

n(P( A)) = 1024 = 210 ⇒ n( A) = 10 n(A ∪ B) = 15 n(P(B)) = 32 = 25 ⇒ n(B) = 5 We know n(A ∪ B) = n{A) + n(B) – n(A ∩ B) (i.e.) 15 = 10 + 5 – n(A ∩ B) ⇒ n(A ∩ B) = 15

Step-by-step explanation:

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