Question

If n^P4 = 12 x n^P2 ,
the n is equal to​

Answer 1

Answer:

n(n-1) [(n-2)(n-3)-12]=0

n(n-1) (n^2-5n+6-12)=0

n(n-1) (n^2-5n-6)=0

n(n-1) [n^2-(6-1)n-6]=0

n(n-1) [n^2-6n+n-6]=0