Question

If N square + 7N +4 divisible by 11, find the remainder when Nsquare + 7N +4 is divided by 121 . Here N is a natural number. Find n

Answer 1

The remainder when N² + 7N +4 is divided by 121 =  81

Step-by-step explanation:

Given: N² + 7N +4 divisible by 11

Find: The remainder when N² + 7N +4 is divided by 121.

Solution:

N² + 7N +4 is divisible by 11 means that 11 is a root of the equation.

Let's substitute N = 11, we get:

= 121 + 77 + 4

 = 202

So now, N² + 7N +4 / 121 = 202 /121

  = 1.7

Quotient = 1 and Remainder =  81