If n^(th) division of main scale coincides with (n + 1)^(th) divisions of vernier scale. Given one main scale division is equal to 'a' units. Find the least count of the vernier.
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Hence the least count of the vernier is a / n + 1
Explanation:
- Given data states that the nth division on main scale coincide with (n+1)th division of Vernier scale, least count has to be calculated.
- Least count is the difference between the main scale division (MSD) and the Vernier scale division (VSD).
Additional data is that 1 MSD equals "a", therefore,
n MSD = (n+1) VSD
=> (n / n+1) MSD = 1 VSD
1 MSD = a
1 VSD = (n / n+1 x a )
Least count = a - ( na / n +1) = a / n + 1
Hence the least count of the vernier is a / n + 1
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