If n th term of a sequence is 3n+2 then find its first term
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T1=3(1)-2=1
T2=3(2)-2=4
T3=3(3)-2=7
So the terms 1,4,7,…….. with a common difference of 3
So it is an AP
10th term=a+(10–1)d=a+9d=1+2728
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