If n times n th term of an AP is equal to m times the m th term.Prove that (m + n) th
term is equal to zero.
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Step-by-step explanation:
Let the first term be 'a' and common difference be 'd'.
In question,
= > m times of mth term = n times of nth term
= > m{a + (m - 1)d} = n{a + (n - 1)d}
= > am + md(m - 1) = an + nd(n - 1)
= > am - an = nd(n - 1) - md(m - 1)
= > a(m - n) = d(n² - n) - d(m² - m)
= > a(m - n) = d(n² - n - m² + m)
= > a(m - n) = d(n² - m² + m - n)
= > a(m - n) = d{(n - m)(n + m) + 1}
= > a(m - n) = d(m - n){ -(n + m) + 1)
= > a = - d(n + m - 1)
Thus, m + n th term:
= > a + (m + n - 1)d
= > - d(n + m - 1) + (m + n - 1)d
= > 0
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