Question

if N times the Nth term of AP is equal to the M times the Mth term of AP then find (M+N)th term ?​

Answer 1

Answer:

Given,

nth term of AP =tn=a+(n−1)d

mth term of AP =tm=a+(m−1)d

⇒mtm=ntn

m[a+(m−1)d]=n[a+(n−1)d]

m[a+(m−1)d]−n[a+(n−1)d]=0

a(m−n)+d[(m+n)(m−n)−(m−n)]=0

(m−n)[a+d((m+n)−1)]=0

a+[(m+n)−1]d=0

But tm+n=a+[(m+n)−1]d

∴tm+n=0

Answer 2

Solution in above attachment