Question

If n(U)=100, n(A)= 50, n(B)=20 and
n(An B) = 10, then n{(AUB)'} =​

Answer 1

Answer:

see the attachment ⬆️⬆️!!....

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Answer 2

Given,

• n(U)=100
• n(A) = 50
• n(B) = 20
• n(A ∩ B) = 10

To find,

• n{(AUB)'}

Solution,

We can simply find the value of n{(AUB)'} by using the following formula:

     n{(AUB)'} = n(U) - n(AUB)      (*)

n(U)=100

n(A) = 50

n(B) = 20

n(A ∩ B) = 10

Using n(A∪B) = n(A) + n(B) -n(A∩B)

                       = 50 + 20 - 10

                        = 70-10

          n(A∪B)  = 60

Now, using (*), we get

          n{(AUB)'} = n(U) - n(A∪B)

                          = 100-60

          n{(AUB)'}  = 40

Hence, if n(U)=100, n(A)= 50, n(B)=20 and n(An B) = 10, then n{(AUB)'} = 40.​