Question

If n(U) =360, n(A)=240 and n(B)=160, then find: (i) the maxmimum value of n(AnB)

Answer 1

Step-by-step explanation:

maxmimum value of n(AnB)=160

if in n(U) u refers whole that is AUB then:

we know that,

n(AnB)=n(A)+n(B)-n(U)

n(AnB)=240+160-360

n(AnB)=40.