If n (u)= 40, n(AUB) = 31, then find n(A' intersection B')
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N(A'nB')=n(AUB)' ----->De Morgan's law.
Therefore, n(AUB)'=n(U)-n(AUB)=40-31=9
So, n(A'nB')=n(AUB)'=9
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