Math, asked by hme9888, 24 days ago

If n(U) = 400, n(A) = 260, n(B) = 340 where U is the
universal set, then the least value of n(ANB) is

Answers

Answered by dshelar338
2

Answer:

200

Step-by-step explanation:

n(AnB) = n(U) -n(A)+ n(B)

= 400 - 260+340

= 400 - 600

= 200

Answered by sangeeth97sl
0

Answer:

200 is the Answer

Step-by-step explanation:

N(U)= N(A)+N(B)- N(ANB)
400= 260+340-N(ANB)
400=600-N(ANB)
200= N(ANB)

A universal set which is (usually denoted by U) which is a set which has elements of all the related sets, without any repetition of elements. For Example if A and B are two sets, such as A = {1,2,3} and B = {1,x,y,z}, then the universal set associated with these two sets is given by U={1,2,3,x,y,z}.


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