If n (U)= 48,n(A)= 28, n(B)=33 and n(B-A)=12 ,then n(A n B)c is
Answers
n(AnB) = 21
Step-by-step explanation:
n(B) = n(AnB) + n(B-A)
Given ,
n(B) = 33
n(B-A) = 12
=>> 33 = n(AnB) + 12
=>> n(AnB) = 33-12 =21
Given :
n(U) = 48 , n(A) = 28 , n(B) = 33 and n(B - A) = 12
To find :
Solution :
Step 1 of 2 :
Find the value of n(A ∩ B)
Here it is given that n(U) = 48 , n(A) = 28 , n(B) = 33 and n(B - A) = 12
Now , n(B - A) = 12
⇒ n(B) - n(A ∩ B) = 12
⇒ 33 - n(A ∩ B) = 12
⇒ n(A ∩ B) = 33 - 12
⇒ n(A ∩ B) = 21
Step 2 of 2 :
= n(U) - n(A ∩ B)
= 48 - 21
= 27
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