Math, asked by harmesh02, 9 months ago

If n (U)= 48,n(A)= 28, n(B)=33 and n(B-A)=12 ,then n(A n B)c is

Answers

Answered by manjunpai2000
5

n(AnB) = 21

Step-by-step explanation:

n(B) = n(AnB) + n(B-A)

Given ,

n(B) = 33

n(B-A) = 12

=>> 33 = n(AnB) + 12

=>> n(AnB) = 33-12 =21

Answered by pulakmath007
0

\displaystyle \sf{  n{(A \cap B)}^{c}}  = 27

Given :

n(U) = 48 , n(A) = 28 , n(B) = 33 and n(B - A) = 12

To find :

\displaystyle \sf{  n{(A \cap B)}^{c}}

Solution :

Step 1 of 2 :

Find the value of n(A ∩ B)

Here it is given that n(U) = 48 , n(A) = 28 , n(B) = 33 and n(B - A) = 12

Now , n(B - A) = 12

⇒ n(B) - n(A ∩ B) = 12

⇒ 33 - n(A ∩ B) = 12

⇒ n(A ∩ B) = 33 - 12

⇒ n(A ∩ B) = 21

Step 2 of 2 :

\displaystyle \sf{ Find  \: the \:  value  \: of \:  \:  n{(A \cap B)}^{c}}

\displaystyle \sf{  n{(A \cap B)}^{c}}

= n(U) - n(A ∩ B)

= 48 - 21

= 27

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