If n(u) = 700, n(A) = 200, n(B) = 300 and
n(An B) = 100, find n A'B).
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Answer:
n(A∩B)=n(A∪B)
=n(u)−n(A∪B)
=n(u)−{n(A)+n(B)−n(A∩B)}
=700−{200+300−100}=300
Step-by-step explanation:
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