Question

if n(X)=50, n(A)=30, n(A intersection B) = 12 and n(A union B)')=15, then find n(B-A)

Please give correct answer with steps
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Answer 1

n(X) = 50

n(AXB)' = 15

=> n(AXB) = n(X) - n(AXB)'

= 50 - 15 = 35

n(AXB) = n(A) + n(B) - n(​​A∩B)

35 = 30 + n(B) - 12

(taking -12 and 30 to the other side...)

n(B) = 35 +12 - 30 = 47 - 30 = 17

n(B-A) = n(B) - n(​​A∩B) = 17 - 12 = 5

Answer 2

Answer:

Hey friend

here is your answer:-

GIVEN-n (A)=15

n (A union B)=29

n (A intersection B)=7

TO FIND-n (B)=?

n (A union B )=n (A)+n (B)-n (A intersectionB )

let n (B)=x

29=15+x-7

29=8+x

x=29-8

x=21

therefore n (B)=21

Hope it helps you

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