Question

If n+y+z=8 and xy + yz + zx=20.Find the value of x3+y3+z3-3xyz​

Answer 1

Step-by-step explanation:

x + y + z = 8

वर्ग करने पर

(x + y + z)² = 64

x²+y²+z²+2(xy+yz+zx) = 64

x² + y² + z² + 2(20) = 64

x² + y² + z² = 64 - 40

x² + y² + z² = 24

x³ + y³ + z³ - 3xyz

=(x+y+z)(x²+y²+z² -xy-yz-zx)

=(x+y+z)(x²+y²+z²-(xy+yz+zx))

= 8(24 - 20)

= 8 * 4 = 32