Question

If n2 gas is bubbled through water at 293 k

Answer 1

If n2 gas is bubbled through water at 293 k

Answer 2

$\huge \mathfrak \red {answer}$

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let the number of mole of N2 dissolved in water be n

Henry’s law constant for N2 at 293 K is 76.48 kbar.

according ti henrys law

partial pressure exerted by

N2=Kh × x

x is the mole fraction

mole fraction of N2=x/(x+55.5)

.987=76.48 × 10^3 × x/(x+55.5)

x=.7 milimole

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