Question

If n2 is odd. than n is
(a) also odd
(b) also prime
(c) also even
(d) none of these​

Answer 1

Answer:

Correct answer is

Proof: If n is odd, then n = 2k + 1 for some integer k. Thus, n2 = (2k + 1)2 = 4k2 + 4k + 1 = 2(2k2 + 2k) + 1. If 3n + 2 is odd, then n is odd.

Step-by-step explanation:

Mark me brainly

Answer 2

Answer:

none of this

Step-by-step explanation:

It is none of this because n is not a number it is a English alphabet and alphabet is not either odd,even or prime