Question

If, n21 and n31 be the refractive indices of medium number 2 and 3, respectively with
respect to medium 1, then the value of refractive index of medium 3 with respect to
medium 2 is
a) n21 +n31 (b) n21/ n31 (c) n31/n21 (d) n21 ×n31​

Answer 1

c hi this is correct answer

Answer 2

Answer:

correct option is (c)

Explanation:

n21=

$\frac{speed \: of \: medium \: 1}{speed \: of \: medium \: 2}$

n31=

$\frac{speed \: of \: medium \: 1}{speed \: of \: medium \: 3}$

So,

$\frac{n31}{n21}$

will give us:

$\frac{speed \: of \: medium \: 1}{speed \: of \: medium \: 3} \times \frac{speed \: of \: medium \: 2}{speed \: of \: medium \: 1} = \\ \frac{speed \: of \: medium \: 2}{speed \: of \: medium \: 3} = n32$

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