Question

if na is avogadro's number then number of valence electrons in 4.2 g of nitrate ions n^3- is

Answer 1

Answer:

N is the Avogadro number which is equal to

= 6.022 × 10^23

molar mass of nitrate ion is 42g

so, 4.2g nitrate ion contains 4.2/42 × N

= N/10 molecules

= 6.022×10^23/10 × 21 electrons

( since one mole of nitrate Ion contains 21 electrons)

= 126.462 ×10^22

= 126 × 10^22 electrons