Question

If Na is the avagadro no than find the no of electron in 4.2gram of nitride

Answer 1

Answer:

Given mass= 4.2g

Molar mass of N3^- (azide ion) = 14*3= 42

Therefore, No. Of moles of azide ion = given mass/ molecular mass= 4.2/42= 0.1 moles

No. of valence electrons in one nitrogen atom = 5

No. of valence electrons in azide ion (N3^-) ( N=N=N ) is =(5*3)+1=16electrons

Therefore, total no. of valence electrons in 4.2g of azide (N3^-) ion = no. of moles of azide ion * no. of valence electrons in one azide ion * Avogadro's constant

= 0.1* 16* 6.022*10^23

=1.6* 6.022*10^ 23

=9.6352* 10^23 valence electrons

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Explanation: