if NaCl is doped with 10 ^-2 mole percentage of Strontium chloride what is the concentration of cation vacancy
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Explanation:
1 Cation of Sr2+ will create 1 cation vacancy in Nacl. Therefore the number of cation vacancies created in the lattice of Nacl is equal to the number of divalent Sr2+ ions added. Now the concentration of cation vacancy on being doped with 10-3 mol% of Srcl2.
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