Question

If NaCl is doped with 10^-3 mol% SrCl2, then the concentration of cation vacancies will be

a) 1 x 10^-3 mol%
b) 2 x 10^-3 mol%
c) 3 x 10^-3 mol%
d) 4 x 10^-3 mol%

URGENT PLEASE!!!

Answer 1

No. of cationic vacancies will be eq to no of Sr2+ ions which have replaced 2 Na+ ions. So, conc. of cationic vacancies = conc. of  SrCl2 = 10^-3mol%(a).