Question

If NaCl is doped with 10⁻⁴ mol % of SrCl₂, the concentration of cation vacancies will be ($N_A$ = 6.02 × 10²³ mol⁻¹)
(a) 6.02 × 10¹⁶ mol⁻¹
(b) 6.02 × 10¹⁷ mol⁻¹
(c) 6.02 × 10¹⁴ mol⁻¹
(d) 6.02 × 10¹⁵ mol⁻¹

Answer 1

see attachment........................................................