Question

if NaCl is doped with 4 x 10-2mol% of CaCl2 , concentration of cation vacancy per mole is
(a)
3.12 x 1020
(b) 6.02 x 1020
(c)
1.204 x 1019
(d)
2.408 x 1020

Answer 1

Answer:

$12 \times 1020$