Question

if nancy gives an interest of rs 45 for 1 year at 9% rate p.a. what is the sum she has borrowed

Answer 1

i= 45
r=9%
t=1 year
si=(p*r*t)/100
hence, p= (si*100)/r*t
p= (45*100)/1*9
p=500

hence, amount or sum borrowed is 500-45 = 455

Answer 2

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The sum borrowed is Rs.500.

Step-by-step explanation:

Given : If Meena gives an interest of Rs.45 for one year at 9% rate p.a.

To find : What is the sum she has borrowed ?

Solution :

Applying interest formula,

I= P*T*R

Where, I=Rs.45 is the interest

R=9%=0.09 is the interest rate

T=1 year is the time

P is the principal or sum

Substitute the value in the formula,

45 = p*0.09*1

P= 45/0.09

P= 500

Therefore, The sum borrowed is Rs.500.